Solving Exponential Equations with Compatible Bases

8.4: Solving Exponential Equations with Compatible Bases. Original editorial SAT preparation with three worked examples, ten flashcards, and thirty practice questions. Educator-review draft.

Lesson 4 of 63 parts Practice Flashcards
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Equal-base equations

Objective: Solve by equating exponents for an injective exponential base.

Prerequisite skills: exponent laws and solving linear equations. For b>0 and b≠1, the function b^x takes each positive output only once. Therefore b^u=b^v implies u=v. This avoids logarithms when both sides have compatible bases. Common error: equating exponents while the bases still differ. Restrictions and interpretation: Match powers only after obtaining equal positive bases other than 1.

Formulas

  • bu=bv⇒u=vforb>0,b≠1b^u=b^v ⇒ u=v for b>0, b≠1

Worked examples

Try itSolve 3^(2x + 1) = 3^47.Show answer

The positive base 3 is not 1, so equate exponents: 2x+1=47. Subtract 1 and divide by 2: x=23. Therefore the requested answer is 23.

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